The reaction of aqueous iron(II) sulfate and aqueous barium nitrate is represented by the balanced net ionic equation.
SO42-(aq) + Ba2+(aq) → BaSO4(s)
Give the balanced formula equation for the reaction. Include the states.
FeSO4(aq) + Ba(NO3)2(aq) ==> BaSO4(s) + Fe(NO3)2(aq)
Sure, here's the balanced formula equation for the reaction:
Ba(NO3)2(aq) + FeSO4(aq) → BaSO4(s) + Fe(NO3)2(aq)
But let me tell you, this chemical reaction is quite the "barium-gain". You see, the barium nitrate solution just couldn't resist the sul-fate of the iron(II) sulfate, so they decided to have a little "aqueous dance-off". In the end, they formed a solid compound called barium sulfate (BaSO4) which gracefully settled at the bottom, leaving behind some nitrate ions and iron(II) nitrate solution. Quite a "solid" performance I must say!
The balanced formula equation for the reaction of aqueous iron(II) sulfate and aqueous barium nitrate is:
Ba(NO3)2(aq) + FeSO4(aq) → BaSO4(s) + Fe(NO3)2(aq)
To write the balanced formula equation for the reaction, we need to identify the reactants and products and then balance the equation.
The reactants are aqueous iron(II) sulfate (FeSO4) and aqueous barium nitrate (Ba(NO3)2). The products are solid barium sulfate (BaSO4).
The formula for iron(II) sulfate is FeSO4, while the formula for barium nitrate is Ba(NO3)2.
To balance the equation, we need to ensure that there is an equal number of each type of atom on both sides.
First, let's write the formula equation with the correct formulas:
FeSO4(aq) + Ba(NO3)2(aq) → BaSO4(s)
Next, we need to balance the equation by adjusting the number of each type of atom on both sides.
In this case, we can see that we have 1 Ba on both sides. We also have 1 S on both sides. However, on the left side, we have 1 Fe and 4 O, while on the right side, we have 1 S and 4 O. To balance the Fe and O, we need to have the same number on both sides.
We can balance these by adding a coefficient of 1 in front of FeSO4 on the left side:
FeSO4(aq) + Ba(NO3)2(aq) → BaSO4(s) + FeSO4(aq)
Now, we have 1 Fe, 1 Ba, 1 S, and 4 O on both sides, which means the equation is balanced.
The balanced formula equation for the reaction is:
FeSO4(aq) + Ba(NO3)2(aq) → BaSO4(s) + FeSO4(aq)