A 15.0 Ohms resistor is connected in series to a 120V generator and two 10.0 Ohms resistors that are connected in parallel to each other.

-What is the total resistance of the load?
-What is the magnitude of the circuit current?
-What is the current in one of the 10.0 Ohms resistors?
-what is the potential difference across 15.0 Ohms resistor?

for the two in parallel

1/10 + 1/10 = 2/10
so Req = 5 Ohms
add the 15 to get total R = 20 Ohms
i = V/R = 120/20 = 6 amps total
half of the current through each = 3 amps
V = i R = 6*15 = 90 Volts

Why did the resistor go on a diet? Because it wanted to become a lighter load!

- To find the total resistance of the load, we can start by finding the equivalent resistance of the two 10.0 Ohms resistors connected in parallel. Let's call this resistance Rp. Using the formula 1/Rp = 1/10 + 1/10, we can simplify to 1/Rp = 2/10 or Rp = 5 Ohms. Then, the total resistance of the load is the sum of the 15.0 Ohms resistor and the equivalent resistance of the parallel resistors, giving us 15 + 5 = 20 Ohms.

- To find the magnitude of the circuit current, we can use Ohm's law, which states that V = IR, where V is the voltage, I is the current, and R is the resistance. In this case, the voltage is 120V and the total resistance is 20 Ohms. So, I = V/R = 120/20 = 6 Amperes.

- Since the two 10.0 Ohms resistors are connected in parallel, they have the same voltage across them. Therefore, the current passing through each of the 10.0 Ohms resistors is the total circuit current, which is 6 Amperes.

- As for the potential difference across the 15.0 Ohms resistor, we can once again use Ohm's law. The voltage across the 15.0 Ohms resistor is V = IR = 6 * 15 = 90 Volts. So, the potential difference across the 15.0 Ohms resistor is 90 Volts.

I hope you liked the circuitry comedy! If you have any more electrical questions, feel free to ask!

To find the total resistance of the load, we need to calculate the equivalent resistance of the two 10.0 Ohms resistors in parallel first. Let's call this resistance Rp.

To calculate Rp, we use the formula:
1/Rp = 1/R1 + 1/R2
where R1 and R2 are the resistances of the two resistors in parallel.

Plugging in the values:
1/Rp = 1/10.0 + 1/10.0
1/Rp = 2/10
1/Rp = 0.2
Rp = 1/0.2
Rp = 5.0 Ohms

Now, to find the total resistance, we add the resistance of the 15.0 Ohms resistor to Rp:
Rtotal = 15.0 + 5.0
Rtotal = 20.0 Ohms

The total resistance of the load is 20.0 Ohms.

To find the magnitude of the circuit current, we use Ohm's Law (V = IR), where V is the voltage and R is the resistance:
I = V/Rtotal
I = 120/20.0
I = 6.0 Amps

The magnitude of the circuit current is 6.0 Amps.

Since the two 10.0 Ohms resistors are in parallel, they have the same potential difference across them. Therefore, the current passing through each of them is the same.

The current in one of the 10.0 Ohms resistors is 6.0 Amps.

To find the potential difference across the 15.0 Ohms resistor, we use Ohm's Law again:
V = IR
V = 6.0 * 15.0
V = 90.0 Volts

The potential difference across the 15.0 Ohms resistor is 90.0 Volts.

To answer these questions, we need to apply the principles of series and parallel connections in electrical circuits.

1. Total resistance of the load:
The resistors connected in parallel can be simplified to a single equivalent resistor. The formula for calculating the equivalent resistance of resistors in parallel is:
1/Req = 1/R1 + 1/R2 + ... + 1/Rn

In this case, we have two 10.0 Ohms resistors in parallel, so we can calculate the equivalent resistance as follows:
1/Req = 1/10.0 + 1/10.0
1/Req = 0.1 + 0.1
1/Req = 0.2
Req = 1/0.2
Req = 5.0 Ohms

Now, the total resistance of the load is the sum of the resistance of the 15.0 Ohms resistor and the equivalent resistance of the two 10.0 Ohms resistors connected in parallel:
Total resistance = 15.0 + 5.0 = 20.0 Ohms

2. Magnitude of the circuit current:
To find the magnitude of the current in the circuit, we can use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R):
I = V/R

In this case, the voltage generated by the generator is 120V, and the total resistance of the load is 20.0 Ohms. Thus, the magnitude of the circuit current is:
I = 120/20.0 = 6.0 A (Amperes)

3. Current in one of the 10.0 Ohms resistors:
Since the two 10.0 Ohms resistors are connected in parallel, they will have the same voltage across them. Hence, the current flowing through each of them will be the same as the circuit current, which is 6.0 A.

4. Potential difference across the 15.0 Ohms resistor:
To find the potential difference across the 15.0 Ohms resistor, we can again use Ohm's Law. The current flowing through the resistor is 6.0 A, and the resistance is 15.0 Ohms. Therefore, the potential difference across the resistor is:
V = I * R = 6.0 * 15.0 = 90.0 V