Calculate the volume (mL) of the solute (CH3)2CO and the volume (L) of the solvent H2O that should be added to prepare 1.36 kg of a solution that is 25.7 g (CH3)2CO per 100. g solution.

Molar Mass (g/mol)
(CH3)2CO 58.05
H2O 18.015

Density (g/mL):
(CH3)2CO 0.7899
H2O 0.9982

Name/Formula:
acetone
(CH3)2CO
water
H2O

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You want 25.7 g ac/100 g soln.

You want 1.36 kg solution or 1360 g.
1359 g soln x (25.7 g Ac/100 g soln) = ?? g acetone.
Or set up a ratio/proportion
(25.7 ac/100 g soln) = (x g ac/1360 g soln) and solving for x gives ?? (should be the same answer but try it and see).

Check it. I think about 349 g acetone but you need to do it more accurately that my estimate).
349 solute/1360 g soln = 0.2567 g/g or 25.7 g/100.

To calculate the volume of the solute (acetone, (CH3)2CO) and the volume of the solvent (water, H2O) needed to prepare the solution, we need to follow the steps below:

Step 1: Calculate the mass of acetone and water required

Since we know the mass of the solution and the mass percentage of acetone in the solution, we can calculate the mass of acetone and water needed to prepare the solution.

Given:
Mass of the solution = 1.36 kg
Mass percentage of acetone = 25.7 g (CH3)2CO / 100 g solution

First, convert the mass of the solution from kg to grams:
1.36 kg = 1.36 * 1000 = 1360 g

Then calculate the mass of acetone and water:
Mass of acetone = Mass of the solution * Mass percentage of acetone
= 1360 g * (25.7 g (CH3)2CO / 100 g solution)
= 349.52 g (CH3)2CO

Mass of water = Mass of the solution - Mass of acetone
= 1360 g - 349.52 g
= 1010.48 g

Step 2: Convert the mass of solute and solvent to volume using their respective densities

Given the densities of acetone and water, we can convert their mass to volume using their densities.

Density of acetone = 0.7899 g/mL
Density of water = 0.9982 g/mL

To convert the mass to volume, we use the formula:
Volume = Mass / Density

Volume of acetone = Mass of acetone / Density of acetone
= 349.52 g / 0.7899 g/mL
≈ 442.39 mL (rounding to two decimal places)

Volume of water = Mass of water / Density of water
= 1010.48 g / 0.9982 g/mL
≈ 1011.78 mL (rounding to two decimal places)

Step 3: Convert the volume of acetone and water to liters

Finally, if you want the volume in liters instead of milliliters, divide the volume in milliliters by 1000.

Volume of acetone in liters = 442.39 mL / 1000
≈ 0.442 L (rounding to three decimal places)

Volume of water in liters = 1011.78 mL / 1000
≈ 1.012 L (rounding to three decimal places)

Therefore, to prepare 1.36 kg of the solution with a mass percentage of 25.7 g acetone per 100 g solution, you should add approximately 0.442 L of acetone ((CH3)2CO) and 1.012 L of water (H2O).