Joshua has a mass of 60kg and stands next to a wall ona frictionless skateboard. If he pushes the wall with a force of 30N, how hard does the wall push on him? Show that Joshua accelerates at .5 m/s2 away from the wall.
Third law - the wall pushes back with 30N.
F = m a
a = F/m = 30N/60kg = 0.5m/s^2
To determine how hard the wall pushes on Joshua, you can use Newton's third law of motion, which states that the force exerted by one object on another is equal in magnitude but opposite in direction. Therefore, the force exerted by the wall on Joshua will also be 30N, but in the opposite direction.
Next, let's calculate the acceleration of Joshua using Newton's second law of motion, which states that F = m*a, where F is the net force, m is the mass, and a is the acceleration.
Given:
Mass of Joshua (m) = 60 kg
Force exerted by Joshua on the wall (F) = 30N
We can rearrange the formula to solve for acceleration (a):
a = F/m
Plugging in the values:
a = 30N/60kg = 0.5 m/s²
Therefore, Joshua accelerates at a rate of 0.5 m/s² away from the wall.
To determine the force exerted by the wall on Joshua, we can apply Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. This means that the force Joshua exerts on the wall (30N) will be matched by the force the wall pushes back on Joshua.
Therefore, the wall will push Joshua with a force of 30N in the opposite direction to his push.
To calculate the acceleration of Joshua, we can use Newton's second law of motion, which states that the sum of the forces acting on an object is equal to the mass of the object multiplied by its acceleration (F = m * a).
In this case, the only force acting on Joshua is the force applied by the wall, which is 30N. Applying the formula, we have:
30N = (mass of Joshua) * (acceleration)
Given that Joshua has a mass of 60kg, we can rearrange the formula to solve for acceleration:
acceleration = 30N / 60kg
acceleration = 0.5 m/s^2
Therefore, Joshua accelerates away from the wall at a rate of 0.5 m/s^2. The force exerted by the wall on him is equal and opposite to the force he exerts on the wall, which is 30N in this case.