A sample of oxalic acid, H2C2O4, is titrated with standard sodium hydroxide, NaOH, solution. A total of 45.2 mL of 0.12 M NaOH is required to completely neutralize 20.0 mL of the acid. What is the concentration of the acid?
Concentration is Molarity, which is moles solute / liters solution.
Would the L of soln be 45.2 mL + 20.0 mL= 65.2 mL = 0.652 L?
And how do I find the moles solute?
VolumeAcid*Molarityacid=Volumebase*Molarity base
VolumeBase=45.1ml
MolarityBase=.12M
VolumeAcid=20ml
Solve for molarity acid.
Yes, you are correct in converting the total solution volume to liters. 65.2 mL is equivalent to 0.652 L.
To find the moles of solute (oxalic acid), we can use the concept of stoichiometry. The balanced equation for the reaction between oxalic acid and sodium hydroxide is:
H2C2O4 + 2NaOH -> Na2C2O4 + 2H2O
From the equation, we can see that 1 mole of oxalic acid reacts with 2 moles of sodium hydroxide.
Given that 45.2 mL of 0.12 M NaOH solution is required to neutralize 20.0 mL of the acid, we can calculate the moles of NaOH used:
moles of NaOH = volume of NaOH solution (in L) x concentration of NaOH (in M)
= 0.0452 L x 0.12 M
= 0.005424 moles
Since the stoichiometry of the reaction is 1:2 (oxalic acid: NaOH), the moles of oxalic acid can be calculated as:
moles of oxalic acid = (moles of NaOH) / 2
= 0.005424 moles / 2
= 0.002712 moles
Now, we can calculate the concentration of the oxalic acid:
Concentration of acid (H2C2O4) = moles of oxalic acid / volume of acid (in L)
= 0.002712 moles / 0.0200 L
= 0.1356 M
Therefore, the concentration of the oxalic acid is 0.1356 M.
To find the concentration of the acid, you first need to determine the number of moles of sodium hydroxide (NaOH) used in the titration.
To find the number of moles of NaOH, you can use the formula n = M * V, where n is the number of moles, M is the molarity of the NaOH solution, and V is the volume of the NaOH solution used.
Given that the molarity of the NaOH solution is 0.12 M and the volume used is 45.2 mL (or 0.0452 L), you can calculate the number of moles of NaOH:
n (NaOH) = 0.12 M * 0.0452 L = 0.005424 moles
Since the balanced chemical equation for the reaction between NaOH and oxalic acid is as follows:
2 NaOH + H2C2O4 -> Na2C2O4 + 2H2O
This means that 2 moles of NaOH react with 1 mole of H2C2O4 (oxalic acid).
So, the number of moles of H2C2O4 can be calculated using the mole ratio:
n (H2C2O4) = 0.005424 moles NaOH * (1 mole H2C2O4 / 2 moles NaOH) = 0.002712 moles H2C2O4
Now, to find the concentration of the oxalic acid (H2C2O4), you divide the number of moles of H2C2O4 by the volume of the acid used in the titration.
Given that the volume of the acid used is 20.0 mL (or 0.0200 L), you can calculate the concentration (molarity) of the oxalic acid:
Concentration (H2C2O4) = 0.002712 moles / 0.020 L = 0.1356 M
Therefore, the concentration of the acid (oxalic acid, H2C2O4) is 0.1356 M.