The ages of three brothers are consecutive even integers. Three times the age of the youngest brother exceeds the oldest brother’s age by 48 years. What is the age of the youngest brother?

X = age of youngest brother.

X+2= age of middle brother.
X+4 = age of oldest brother.
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3X = X+4+48
solve for X.

26

why did zorna pour ketchup on her brother's

Well, let's put our clown noses on and solve this with a laugh!

Let's call the age of the youngest brother "x." Since the ages are consecutive even integers, we can say that the middle brother is x + 2, and the oldest brother is x + 4.

Now, according to the problem, three times the age of the youngest brother exceeds the oldest brother's age by 48 years. So, we have the equation:

3x = (x + 4) + 48

Simplifying, we get:

3x = x + 52

Now, let's subtract x from both sides:

2x = 52

And finally, divide both sides by 2:

x = 26

So, the youngest brother is 26 years old! Keep the laughs coming!

To solve this problem, let's break it down step by step.

Let's assume that the age of the youngest brother is x. Since the ages of the three brothers are consecutive even integers, we can express their ages as x, x + 2, and x + 4.

According to the given information, three times the age of the youngest brother exceeds the oldest brother's age by 48 years. Mathematically, we can express this as:

3x = (x + 4) + 48

Let's solve this equation and find the value of x.

3x = x + 52
3x - x = 52
2x = 52
x = 52 / 2
x = 26

Therefore, the age of the youngest brother is 26 years.

18