### x^3-36x over x^2+7x+6, divided by 6x^2-x^3 over x^2+x

I know the right answer is -1, but I can't seem to get to it. I've gotten as far as [x(x-6)]/1] * 1/[x^2(6-x)], which is then equal to [x(x-6)]/x^2(6-x). And then would I reduce the x and x^2 to 1 and x,