a ball is kicked with a velocity of 12 m/s at an angle of 42 degress above the horizontal. how far away does the ball land?

2 answers

  1. R = range = (V^2/g)*sin(2A)
    2A = 84 degrees; V = 12 m/s, g = 9.81 m/s^2

    Solve for R

    See if you can derive the formula. It used the fact that 2sinA*cos A = sin(2A)

  2. 1,A foot ball is kicked at avelocity of 15m/s at angel of 25 degeres to the horizontal. calculate

    a, the total flight time

    b, the maximum height

    c the range of the ball

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