a ball is kicked with a velocity of 12 m/s at an angle of 42 degress above the horizontal. how far away does the ball land?
2 answers

R = range = (V^2/g)*sin(2A)
2A = 84 degrees; V = 12 m/s, g = 9.81 m/s^2
Solve for R
See if you can derive the formula. It used the fact that 2sinA*cos A = sin(2A)

1,A foot ball is kicked at avelocity of 15m/s at angel of 25 degeres to the horizontal. calculate
a, the total flight time
b, the maximum height
c the range of the ball