I need some help finding the net ionic equation for these two problems:
1. Bromine is added to a dilute solution of sodium hydroxide.
2. Sulfuric acid is added to a solution of lithium hydrogen carbonate.
This is what I have for reactants:
Br2 + NaOH and H2SO4 + LiHCO3.
I'm not sure about 1, since I don't think the rxn makes bromine hydroxide (activity series?)
And for 2, I thought it was a double replacement, but...it isn't? Help plz?
Thanks!
I would write #1 as
Br2 + 2NaOH ==> NaOBr + NaBr + H2O
This is the balanced molecular equation.
Now convert to ions using the following rules.
solids written as molecules
liquids written as molecules
solutions written as ions unless they are weak electrolytes which are written as molecules.
Br2 + 2Na^+ + 2OH^- ==> NaOBr + Na^+ + Br^-^- + H2O
Now cancel ions common to both sides.
1Na^+ can be canceled on each side.
What is left is the net ionic equation.
Br2 + Na^+ + 2OH^- ==>NaOBr + Br^- + H2O
Check my thinking. Check my work.
To find the net ionic equation for the given reactions, we need to first write the balanced chemical equation for each reaction and then identify the spectator ions.
1. Bromine is added to a dilute solution of sodium hydroxide:
The balanced chemical equation for this reaction is:
Br2 + 2 NaOH -> NaBr + NaBrO + H2O
In this reaction, bromine (Br2) reacts with sodium hydroxide (NaOH) to form sodium bromide (NaBr), sodium bromate (NaBrO), and water (H2O).
To find the net ionic equation, we need to identify the ions that actually participate in the reaction. The spectator ions are the ions that do not undergo any chemical change and can be omitted from the net ionic equation.
In this case, sodium ions (Na+) and bromide ions (Br-) are spectator ions since they are present on both sides of the reaction and do not undergo any change.
The net ionic equation for this reaction is:
Br2 + 2 OH- -> BrO- + Br- + H2O
2. Sulfuric acid is added to a solution of lithium hydrogen carbonate:
The balanced chemical equation for this reaction is:
H2SO4 + 2 LiHCO3 -> Li2SO4 + 2 H2O + 2 CO2
In this reaction, sulfuric acid (H2SO4) reacts with lithium hydrogen carbonate (LiHCO3) to form lithium sulfate (Li2SO4), water (H2O), and carbon dioxide (CO2).
To find the net ionic equation, once again, we need to identify the ions that actually participate in the reaction. The spectator ions are the ions that do not undergo any chemical change and can be omitted from the net ionic equation.
In this case, sulfate ions (SO4^2-) and lithium ions (Li+) are spectator ions since they are present on both sides of the reaction and do not undergo any change.
The net ionic equation for this reaction is:
2 H+ + 2 HCO3- -> 2 H2O + 2 CO2
In this net ionic equation, the sulfate ions and lithium ions are omitted as spectator ions, and we focus only on the ions that participate in the reaction, which are the hydrogen ions (H+) and hydrogen carbonate ions (HCO3-).
I hope this helps! Let me know if you have any further questions.
Sure, I can help you find the net ionic equations for these two problems.
1. Bromine is added to a dilute solution of sodium hydroxide:
The reactants are bromine (Br2) and sodium hydroxide (NaOH). In this case, bromine is a halogen and it is not strong enough to displace hydroxide ions from sodium hydroxide. Therefore, no reaction occurs. The net ionic equation is:
No reaction.
2. Sulfuric acid is added to a solution of lithium hydrogen carbonate:
The reactants are sulfuric acid (H2SO4) and lithium hydrogen carbonate (LiHCO3). This reaction is a double replacement reaction. The acid will react with the bicarbonate to form carbonic acid, which will then decompose into carbon dioxide and water. The net ionic equation is:
H2SO4 + LiHCO3 ⟶ CO2 + H2O + Li2SO4
So the net ionic equation for this reaction is:
H+ + HCO3- ⟶ CO2 + H2O
I hope this helps! Let me know if you have any further questions.