A 3006 caliber hunting rifle fires a bullet of
mass 0.0118 kg with a velocity of 505 m/s to
the right. The rifle has a mass of 6.15 kg.
What is the recoil speed of the rifle as the
bullet leaves the rifle?
Answer in units of m/s.
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2 answers

MV = Mv
(.0118)(505) = (6.15) (v)
(5.959) = 6.15v
v = .968943 👍
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V=mv/M. where V=?, m=0.0118kg, v=505m/s, M=6.15kg V=0.0118(505)/6.15 V=5.959/6.15 V=0.969m/s
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