The speed of an automobile of mass 1600 kg increases uniformly from 20 m/s to 30 m/s. What is the increase in its kinetic potential?

Given:
m = 1600 kg
V = 10 m/s

KE = 1/2 m v^2
KE = 1/2 (1600)(10)^2
KE = 80,000 J

Is this right?

No, not even close.

KEincrease=1/2 m (Vf^2-Vi^2)
= 1/2 1600 *(900-400)

To calculate the increase in kinetic energy (KE) of an automobile, first, you need to find the initial kinetic energy (KEi) and the final kinetic energy (KEf).

The formula for kinetic energy is given by:
KE = 1/2 * m * v^2

Where:
KE = Kinetic energy
m = Mass of the object (in this case, the automobile) = 1600 kg
v = Velocity of the object

Given that the initial velocity (vi) is 20 m/s and the final velocity (vf) is 30 m/s, we can calculate the initial kinetic energy as follows:

KEi = 1/2 * m * vi^2
= 1/2 * 1600 * (20)^2
= 1/2 * 1600 * 400
= 320,000 J

Similarly, we can calculate the final kinetic energy as follows:

KEf = 1/2 * m * vf^2
= 1/2 * 1600 * (30)^2
= 1/2 * 1600 * 900
= 720,000 J

The increase in kinetic energy (ΔKE) can be found by subtracting the initial kinetic energy from the final kinetic energy:

ΔKE = KEf - KEi
= 720,000 - 320,000
= 400,000 J

So, the increase in kinetic energy of the automobile is 400,000 J.

Therefore, your calculation is incorrect.