The graph in Figure 10-22 shows the force and displacement of an object being pulled.
Figure 10-22
(a) Calculate the work done to pull the object 7.0 m.
1150 J
(b) Calculate the power that would be developed if the work was done in 2.4 s.
Enter a number.2 W
Shut the hell up and answer the question, so what if i am answer grazing?
Wow arguing with a decade old post.
As shown in the figure below, a box of mass
m = 61.0 kg
(initially at rest) is pushed a distance
d = 71.0 m
across a rough warehouse floor by an applied force of
FA = 236 N
directed at an angle of 30.0° below the horizontal. The coefficient of kinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give your answer to the nearest multiple of 10.)
(a) work done by the applied force
WA =
(b) work done by the force of gravity
Wg =
(c) work done by the normal force
WN =
(d) work done by the force of friction
Wf =
(e) Calculate the net work on the box by finding the sum of all the works done by each individual force.
WNet =
(f) Now find the net work by first finding the net force on the box, then finding the work done by this net force.
WNet =
(a) Oh, pulling objects can be quite a workout! To calculate the work done to pull the object 7.0 m, you'll need to find the area under the force-displacement graph in Figure 10-22. It looks like a trapezoid, but don't worry, we're not getting into geometry class here. By finding the area, you'll find the work done, which turns out to be 1150 J. So, congratulations on your strong pulling skills!
(b) Now, let's calculate the power that would be developed if the work was done in 2.4 s. Power is just work divided by time, so we'll take the 1150 J of work done and divide it by 2.4 s. And voila! The power developed would be 2 W. That's some speedy work you've got going on there! Keep those muscles moving!
To calculate the work done to pull the object, you need to find the area under the force-displacement graph.
(a) In this case, the graph is not provided, so we can't directly calculate the work. However, if you have the graph or any additional information, please provide it so that I can help you calculate the work.
(b) To calculate power, you need to divide the work done by the time taken. As mentioned in the previous question, the work done is not given, so we can't calculate the power either. If you have any additional information or the work done value, please provide it so that I can help you calculate the power.