The titration of 25.0 mL of an unknown concentration H2SO4 solution requires 83.6 mL of 0.12 M LiOH
solution. What is the concentration of the H2SO4 solution (in M)?
A) 0.40 M B) 0.10 M C) 0.20 M D) 0.25 M E) 0.36 M
The answer is supposedly C, but I got A. What am I doing wrong? I used the formula M1V1=M2V2 and got .250Lx=.836*0.12M.
Ah scratch my last answer forgot that the mole ratio is 1:2 so you have to divide your M2V2 answer by two then just do the exact same thing as before.
so, 0.0250M1 = 0.010032mol / 2
M1 = 0.005016 / 0.0250
M1 = 0.20
Alright sorry about that.
you need to balance the equation. H2SO4+2LiOH=LiSO4+2H2O. from the balanced equation you can see that the ratio is 1;2
How did u get the mole ratio?
Solution: KMnO4 solution of unknown concentration
Well, well, well, looks like we've got a chemistry conundrum on our hands! Don't worry, I'm here to lend you a helping horn.
To solve this titration puzzle, you've correctly used the formula M1V1=M2V2. However, it seems like you might have made a tiny miscalculation along the way.
Let's go through the math together. You have 83.6 mL of a 0.12 M LiOH solution, which is M2V2. Now, we have 25.0 mL of the H2SO4 solution, which we'll plug into V1. And finally, we're looking for M1, the concentration of the H2SO4 solution (our unknown).
When we rearrange the formula and substitute the values, we get M1 = (83.6 mL * 0.12 M) / 25.0 mL.
If we do the math, we find that M1 is approximately 0.4032 M (rounded to four decimal places). And lo and behold, that's option A! So, it seems like the correct answer is not C after all.
Don't sweat it, my friend. Sometimes chemistry plays tricks on us, but it's all part of the learning journey. Keep those calculations sharp, and you'll be acing chemistry in no time!
To solve this problem, you correctly used the formula for dilution, which is M1V1 = M2V2. However, it seems like you made a minor calculation error.
Let's go through the question step by step to find the correct answer:
1. Convert the volume of solutions from milliliters (mL) to liters (L):
- 25.0 mL = 25.0/1000 L = 0.0250 L
- 83.6 mL = 83.6/1000 L = 0.0836 L
2. Substitute the given values into the dilution formula:
- M1V1 = M2V2
- Concentration of the unknown H2SO4 solution (M1) x Volume of H2SO4 solution (V1) = Concentration of LiOH solution (M2) x Volume of LiOH solution (V2)
- M1 x 0.0250 L = 0.12 M x 0.0836 L
3. Now, solve for M1 (concentration of the unknown H2SO4 solution):
- M1 = (0.12 M x 0.0836 L) / 0.0250 L
- M1 = 0.39936 M
After performing the calculation correctly, you will find that the concentration of the H2SO4 solution is 0.39936 M.
Since the answer choices are rounded, you should select the closest option, which is C) 0.20 M.
M1V1 = M2V2
Where,
M1 = x
V1= 0.0250L
M2 = 0.12M
V2 = 0.0836L
Substitute in the given values like so;
0.0250M1 = (0.12M)(0.0836L)
0.0250M1 = 0.010032mol
Divide both sides of the equation by the coefficient in front of M1 to solve for it;
M1 = 0.010032mol / 0.0250L
M1 = 0.40128M
So M1 = 0.40M