Write the complete balanced molecular, ionic,and net ionic equations for the reaction of nickle II chloride + sodium phosphate. Which product,if any, is a precipitate?

is NickleII phosphate soluble in water?

(a) 3NiCl2(aq) + 2Na3PO4(aq) ---> Ni3(PO4)2(s) + 6NaCl

(b) 3Ni^+2(aq) + 6Cl^-(aq) + 6Na^+(aq) + 2PO4^-3(aq) ---> Ni3(PO4)2(s) + 6Cl^-(aq) + 6Na^+(aq)

(c) [Cancel out the ions that have not changed to get the net ionic equation]

To write the complete balanced molecular equation, ionic equation, and net ionic equation for the reaction of nickel(II) chloride and sodium phosphate, we need to understand the chemical formulas of the reactants and products involved.

Reactants:
Nickel(II) chloride: NiCl2
Sodium phosphate: Na3PO4

Step 1: Write the balanced molecular equation by combining the reactants to form the products without breaking them into their ions.

NiCl2 + Na3PO4 → Ni3(PO4)2 + 6NaCl

Next, let's break down the equation into its constituent ions to form the balanced ionic equation.

Step 2: Write the balanced ionic equation by representing all of the strong electrolytes dissociated into their respective ions.

Reactants:
NiCl2 → Ni2+ + 2Cl^-
Na3PO4 → 3Na+ + PO4^3-

Products:
Ni3(PO4)2 → 3Ni^2+ + 2PO4^3-
6NaCl → 6Na+ + 6Cl^-

Now let's write the net ionic equation by excluding the spectator ions (ions that appear unchanged on both sides of the equation).

Step 3: Write the net ionic equation by removing the spectator ions.

Net Ionic Equation:
Ni2+ + 2PO4^3- → Ni3(PO4)2

The net ionic equation reveals that nickel(II) ions react with phosphate ions to form nickel(II) phosphate.

Finally, let's determine if any of the products formed is a precipitate.
A precipitate is an insoluble solid formed from the combination of two aqueous solutions. In this case, if nickel(II) phosphate (Ni3(PO4)2) is insoluble, it will be the precipitate.

To determine if nickel(II) phosphate is a precipitate, we can consult a solubility table. According to the solubility rules:
- Most phosphates are insoluble, except those of alkali metals and ammonium.

As nickel(II) phosphate contains nickel(II) ions and phosphate ions, which are not alkali metal or ammonium compounds, nickel(II) phosphate is insoluble.

Therefore, the precipitate in this reaction is nickel(II) phosphate (Ni3(PO4)2).