If I push a 10kg box with 50.0N of force forward and the box has a coefficient of kinetic friction of .25 what is the forward acceleration of the box?

1 answer

  1. find the weight
    10* 9.8 = 98 N
    times friction coef = .25*98 = 24.5 N friction
    net force = 50 - 24.5 = 25.5 N
    F = m a
    25.5 = 10 a
    a = 2.55 m/s^2

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