Thanks for showing some evidence of your own work.

The mass will be released when the spring & mass reach the equilibrium position, (x=0), together. That takes 1/4 of the period, or 1.075 s. After release, the object travels at constant velocity. It is not clear whether by "release" they mean separation from the spring or the release of the object from the initial position.

For the velocity of the object when it is released (V) , used conservation of energy.

(1/2)kX^2 = (1/2)M V^2.

X is the initial spring compression.

You can figure out what k is using the period, P, as follows:

P = 2*pi*sqrt(m/k)