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a 1kg ball is thrown into the air with an initial velocity of 30 m/sec. how much kinetic energy does the ball have?

-how much potential energy does the ball have when it reaches the top of its ascent?

-how high into the air did the ball travel?

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2 answers
  1. Assume potential energy on ground is zero.
    Kinetic energy at 30 m/s
    =(1/2)mv²
    Potential energy at highest point, H from ground
    =mgh
    Equate energies,
    mgh=(1/2)mv²
    h=(1/2)mv²/mg
    =v²/(2g)

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  2. A girl hold a 2kg netball at height of 1,5 m above the ground and throws is vertically upwards at a velocity of 4 m.s.it reaches its turning point and falls back to the ground

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