How many grams of H3PO4 are in 175 Ml of a 3.5 M solution of H3PO4?
(3.5mol/1 L)x(.175L)=.6125moles of H3PO4
.6125x(98g/1 mol)=60.025g
To determine the number of grams of H3PO4 in a solution, we need to use the formula:
mass (grams) = volume (liters) × concentration (M) × molar mass (grams/mole)
First, let's calculate the number of moles of H3PO4 in the solution:
moles = volume (liters) × concentration (M)
Since we have 175 mL of a 3.5 M solution, we need to convert the volume to liters:
175 mL ÷ 1000 mL/L = 0.175 L
Now, we can calculate the number of moles:
moles = 0.175 L × 3.5 M = 0.6125 moles
Finally, to find the mass of H3PO4, we need to know the molar mass of H3PO4, which can be calculated as follows:
H: 1.01 g/mol × 3 (three hydrogen atoms) = 3.03 g/mol
P: 30.97 g/mol × 1 (one phosphorus atom) = 30.97 g/mol
O: 16.00 g/mol × 4 (four oxygen atoms) = 64.00 g/mol
Adding these values together, we get:
molar mass of H3PO4 = 3.03 g/mol + 30.97 g/mol + 64.00 g/mol = 98.00 g/mol
Finally, we can calculate the mass of H3PO4:
mass (grams) = 0.6125 moles × 98.00 g/mol = 60.19 grams
Therefore, there are approximately 60.19 grams of H3PO4 in 175 mL of a 3.5 M solution of H3PO4.
To determine the number of grams of H3PO4 in a given volume of a solution, you need to use the molarity and the molecular weight of H3PO4.
Here's how you can calculate it:
1. Determine the molar mass of H3PO4.
- H3PO4 contains 3 hydrogen atoms (1.01 g/mol each), 1 phosphorus atom (30.97 g/mol), and 4 oxygen atoms (16.00 g/mol each).
- The molar mass of H3PO4 is 3(1.01) + 30.97 + 4(16.00) = 98.00 g/mol.
2. Convert the volume of the solution from milliliters (mL) to liters (L).
- 175 mL = 175/1000 = 0.175 L.
3. Use the molarity and the volume to calculate the number of moles of H3PO4.
- Moles of H3PO4 = Molarity x Volume
- Moles of H3PO4 = 3.5 mol/L x 0.175 L = 0.6125 moles.
4. Calculate the grams of H3PO4 using the moles and molar mass.
- Grams of H3PO4 = Moles of H3PO4 x Molar mass
- Grams of H3PO4 = 0.6125 moles x 98.00 g/mol = 60.07 grams.
Therefore, there are approximately 60.07 grams of H3PO4 in 175 mL of a 3.5 M solution of H3PO4.
I assume you mean 175 ml (milliliters).
There will be 3.5 moles x 0.175 liters or 0.6125 moles of H3PO4.
Uning the molar mass of that compound, Which you are surely able to compute, convert that number of moles to grams.
When I went to school long ago, molar mass was called molecular weight. It is still computed the same way.