A child holds a sled on a frictionless, snow-

covered hill, inclined at an angle of 33◦.

If the sled weighs 56 N, find the force ex-
erted on the rope by the child.
Answer in units of N.

your answer was wrong

force downhiull= 56sin33

So the rope tension has to be this same value.

Well, if the sled is on a frictionless surface, that means it's going to slide down the hill really fast! Wheeeee! But anyways, back to the question.

To find the force exerted on the rope by the child, we need to use some trigonometry. The force exerted by the child can be broken down into two components: one parallel to the slope and one perpendicular to the slope.

The force parallel to the slope is the one we're interested in. We can find that by taking the weight of the sled and multiplying it by the sine of the angle of the hill. So, the force exerted on the rope by the child is:

Force = Weight of the sled * sin(angle)

Plugging in the values, we get:

Force = 56 N * sin(33◦)

Now, I'm not great with numbers, but if you plug that into a calculator, you'll get your answer in units of N. Voilà!

To find the force exerted on the rope by the child, we need to analyze the forces acting on the sled.

First, let's consider the weight of the sled. The weight is the force exerted by gravity on the sled and it always acts vertically downward. We are given that the weight of the sled is 56 N. Since the sled is on a frictionless, snow-covered hill, the weight of the sled can be split into two components: one parallel to the inclined plane and one perpendicular to the inclined plane.

The component of the weight parallel to the inclined plane can be found using the formula:
Force parallel = weight * sin(angle),
where the angle is the angle of the hill. In this case, the angle is 33 degrees.

Force parallel = 56 N * sin(33°) = 30.07 N.

The force exerted on the rope by the child is equal in magnitude and opposite in direction to the force parallel. So, the force exerted on the rope by the child is also 30.07 N.

oops.

force downhill=56*9.8Sin 33