which starting material is the limiting reagent in this procedure? which reagent is used in excess?How great is the molar excess(how many times greater)?
With no equation....
The equation is: Acetic acid + Isopentyl alcohol ---> Isopentyl acetate.
Of course there is a mundane acid catalyst. How great is the molar excess knowing that acetic acid is in excess and isopentyl alcohol is limited?
To determine the limiting reagent and the reagent in excess, you need to know the balanced chemical equation for the procedure. Without that information, I am unable to answer your question accurately. Could you please provide me with the chemical equation or give me more details about the procedure?
To determine the limiting reagent and the reagent in excess, you need to know the balanced chemical equation and the quantities of the reactants used.
1. Write the balanced chemical equation: Start by writing the balanced chemical equation for the procedure you are referring to. This equation will show the reactants and products involved in the reaction.
2. Determine the stoichiometric ratio: Once you have the balanced chemical equation, identify the stoichiometric ratio between the reactants. This ratio is based on the coefficients of the balanced equation and shows the number of moles of each reactant required to complete the reaction.
3. Calculate the moles of each reactant: Next, calculate the number of moles of each reactant used in the procedure. This can be done by dividing the given masses of the reactants by their respective molar masses.
4. Identify the limiting reagent: The limiting reagent is the reactant that is completely consumed in the reaction and determines the maximum amount of product that can be formed. To determine the limiting reagent, compare the moles of each reactant calculated in step 3 with the stoichiometric ratio from step 2. The reactant that yields fewer moles of the product is the limiting reagent.
5. Calculate the molar excess: The reagent that is not the limiting reagent is the one in excess. To determine the molar excess, compare the moles of the reactant in excess with the moles of the limiting reagent. Divide the moles of the excess reagent by the moles of the limiting reagent to find out how many times greater the excess is.
By following these steps, you will be able to determine which starting material is the limiting reagent, which reagent is in excess, and how great the molar excess is.