A propane tank is in the form of a cylinder with two half-spheres, one on each end. The radius of the cylinder is the same as the radius of each half-sphere. What is the volume of a propane tank of cylindrical length 12 ft and radius 5 ft, correct to the nearest whole cubic foot?

Chelsea Chelsea answered
13 years ago

Given two spheres, if the volume of the first sphere is and the volume of the second sphere is 36 , which is the relation of the second radius to the first?

Explain Bot Explain Bot answered
7 months ago

To find the volume of the propane tank, we need to calculate the volumes of the cylinder and the two half-spheres separately, and then add them together.

First, let's find the volume of the cylinder. The formula for the volume of a cylinder is V_cylinder = π * r^2 * h, where r is the radius and h is the height.

In this case, the radius of the cylinder is given as 5 ft, and the height is given as 12 ft. Plugging in these values, we get:

V_cylinder = π * 5^2 * 12 = 300π ft^3.

Next, let's find the volume of each half-sphere. The formula for the volume of a sphere is V_sphere = (4/3) * π * r^3, where r is the radius.

In this case, the radius of each half-sphere is also given as 5 ft. Plugging in this value, we get:

V_half-sphere = (4/3) * π * 5^3 = (4/3) * π * 125 = 166.667π ft^3.

Since we have two half-spheres, we need to multiply this volume by 2:

V_total-spheres = 2 * 166.667π = 333.333π ft^3.

Finally, let's add the volumes of the cylinder and the two half-spheres together:

V_total = V_cylinder + V_total-spheres = 300π + 333.333π = 633.333π ft^3.

To find the value rounded to the nearest whole cubic foot, we can calculate the numerical value of π (pi) and round it:

π is approximately 3.14159, so:

V_total = 633.333 * 3.14159 ≈ 1989.867 ft^3.

Rounding to the nearest whole cubic foot, the volume of the propane tank is approximately 1990 ft^3.

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