How many grams of ice at -20.1C can be completely converted to liquid at 9.9C if the available heat for this process is 4.58×103 kJ?

For ice, use a specific heat of 2.01 J/(g*C) and Heat of Fusion is = 6.01 kJ/mol.

1 answer

  1. You have to heat all of the ice to 0, then melt it.

    Heat=mcDeltatemp+ Hf*m
    = m(2.01*(21)J/g + 6010J/mol*1mol/18g)
    solve for m in grams

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