f(x) = [3/x^2]  [5/x^7], F(x) is the antiderivative of f(x) with F(1)=0.
F(x) = ?
I have no idea how to approach this problem. The fractions are scaring me.
1 answer

This is really pretty simple, I can't imagine how you are stuck.
INTf(x)= INT 3x^2 dx INT (5x^7)dx
= 3x^1 +5/6 x^6 +C
F(1)=0 = 3+5/6+C=1
solve for C.
F(x) = 3x^1 +5/6 x^6 check my work, it is easy to make a typo