What is the slope of the line perpendicular to the line whose equation is y= -2/3x-5?
perpendicular means the negative reciprocal of the line slope.
m= 3/2
To find the slope of a line perpendicular to another line, we need to determine the negative reciprocal of the slope of the given line.
The given line has an equation in slope-intercept form (y = mx + b), where m represents the slope. From the given equation y = -2/3x - 5, we can see that the slope of the line is -2/3.
To find the slope of the line perpendicular to this line, we take the negative reciprocal of -2/3. To take the reciprocal, we flip the fraction and change its sign. Therefore, the negative reciprocal of -2/3 is 3/2.
Hence, the slope of the line perpendicular to the line y = -2/3x - 5 is 3/2.
To find the slope of a line perpendicular to another line, we need to take the negative reciprocal of the slope of the given line.
The given line has an equation in slope-intercept form: y = mx + b, where m is the slope and b is the y-intercept. In this case, the slope of the given line is -2/3.
To find the slope of the line perpendicular to the given line, we take the negative reciprocal of -2/3.
The negative reciprocal of a value is found by taking its reciprocal (flipping the fraction) and then negating it (adding a negative sign).
So, let's find the negative reciprocal of -2/3:
-2/3 (reciprocal) = -3/2 (flip the fraction)
-3/2 (negate) = 3/2 (add a negative sign)
Therefore, the slope of the line perpendicular to the line y = -2/3x - 5 is 3/2.