Identify any incorrect formulas. explain your answer.

a. Mg2(SO4)3
b. Rb3As
c. BeCl3
d. NaF

a.cross magnesium and sulfate, sulfate has -2 charge and mg +2 charge, same charges cross out, MgSO4

c.chlorine is Cl -1 charge, beryllium has +2 charge, cross charges, BeCl2

Check a.

Check c.

What Mg2(S04)3

Mg2(SO4)3

BeCl3
AsRb3
NaF

a. Mg2(SO4)3 - This formula is incorrect. The correct formula for magnesium sulfate is MgSO4. In this incorrect formula, there are two magnesium ions (Mg2) for every three sulfate ions (SO4), which violates the Law of Definite Proportions.

b. Rb3As - This formula is correct. It represents rubidium arsenide, where there are three rubidium ions (Rb) for every arsenic ion (As).

c. BeCl3 - This formula is correct. It represents beryllium chloride, where there is one beryllium ion (Be) for every three chloride ions (Cl).

d. NaF - This formula is correct. It represents sodium fluoride, where there is one sodium ion (Na) for every fluoride ion (F).

To identify any incorrect formulas, we need to verify if the elements and their respective subscripts are correct and follow the rules for chemical formulas. Let's go through each option and check:

a. Mg2(SO4)3: This is the correct formula for magnesium sulfate. Magnesium, represented by "Mg," has a charge of +2, and sulfate, represented by "SO4," has a charge of -2. The subscripts are correctly written based on the charges of the ions.

b. Rb3As: This is the correct formula for rubidium arsenide. Rubidium, represented by "Rb," is an alkali metal with a charge of +1, and arsenic, represented by "As," is a group 15 element with a charge of -3. The subscripts are correctly written based on the charges of the ions.

c. BeCl3: This is the correct formula for beryllium chloride. Beryllium, represented by "Be," is an alkaline earth metal with a charge of +2, and chloride, represented by "Cl," has a charge of -1. The subscript "3" signifies that there are three chloride ions for each beryllium ion, creating a neutral compound.

d. NaF: This is the correct formula for sodium fluoride. Sodium, represented by "Na," is an alkali metal with a charge of +1, and fluoride, represented by "F," has a charge of -1. The subscripts are correctly written based on the charges of the ions.

Therefore, all of the given formulas are correct.