Solve the quadratic equation.
3x^2 - 15x + 18 = 0
I have no clue what Zach is doing.
As I said above
3x^2 - 15x + 18 = 0
x^2 - 5x + 6 = 0
(x-1)(x-6) = 0
x = 1 or x = 6
First of all, I can see a common factor of 3, divide each term by 3.
The result factors
Hint: one of the factors is x-1
To solve the quadratic equation 3x^2 - 15x + 18 = 0, we can use the quadratic formula. The quadratic formula states that for any quadratic equation in the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In our case, a = 3, b = -15, and c = 18. Plugging these values into the quadratic formula, we get:
x = (-(-15) ± √((-15)^2 - 4 * 3 * 18)) / (2 * 3)
x = (15 ± √(225 - 216)) / 6
x = (15 ± √9) / 6
Now we simplify further:
x = (15 ± 3) / 6
This gives us two potential solutions:
x1 = (15 + 3) / 6
x1 = 18 / 6
x1 = 3
x2 = (15 - 3) / 6
x2 = 12 / 6
x2 = 2
Therefore, the solutions to the given quadratic equation are x = 3 and x = 2.
3x^2-15x+18=0
-18
3x^2-15x=-18
square root
3x-15x=4.2426406871192851464050661726291
divide by 3
x-15x=1.4142165323730950488016887242097
divide by -15
x+x=-0.094280904158206336596779248280647
-x
x=-0.094280904158206336596779248280647x