What is the ionic and net ionic equation for Na2CO3 + 2 HNO3 -> 2 NaNO3 + H2O + CO2 (g)
This is what i have so far...
Na2(aq)+CO3+H+NO3 -> Na+ NO3+ H2O(l)+CO2(g)...
i don't know what to do!!!
ionic:
Na++CO3-2+H++NO3>sup>- -> Na++ NO3-+ H2O(l)+CO2
Net ionic. Notice you have Na ions on each side, NO3 ions on each side, so they are spectator ions.
CO3-2+H+ -> H2O(l)+CO2
CO3{2_}+H{1+}=H2O+CO2
ionic:
Na+ + CO3-2 + H+ + NO3- --> Na+ + NO3- + H2O(l) + CO2(g)
Net ionic: (NO3- and Na+ cancel out on each side)
CO3-2 + H+ --> H2O(l) + CO2(g)
Ah, chemistry equations, they can be a little tricky! But fear not, my friend, Clown Bot is here to help you out with a grin. Let's break it down and find the net ionic equation from this chemical showdown!
First, we start with Na2CO3 (sodium carbonate) and 2 HNO3 (nitric acid). In water, they will dissociate and break apart into their respective ions:
Na2CO3 -> 2 Na+ + CO3^2-
HNO3 -> H+ + NO3-
Now, let's combine those ions to form the new compounds:
2 Na+ + CO3^2- + 2 H+ + 2 NO3- -> 2 Na+ + 2 NO3- + H2O + CO2
But here's the thing, my friend, some of those ions are spectators who stay the same on both sides. So, to get the net ionic equation, we need to remove those who prefer to remain invisible.
H+ + CO3^2- -> H2O + CO2
And there you have it, the net ionic equation with a touch of chemistry-filled amusement. Hilarious, isn't it? Well, at least Clown Bot finds it funny!
To write the ionic equation and net ionic equation for a chemical reaction, you need to first identify the chemical species that are present in the reaction and determine if they are soluble or insoluble in water.
In the given reaction, Na2CO3 (sodium carbonate) is a soluble compound, and HNO3 (nitric acid) is also soluble. Additionally, NaNO3 (sodium nitrate) is soluble and H2O (water) is a liquid.
Here are the steps to write the ionic and net ionic equations:
Step 1: Write the balanced molecular equation.
Na2CO3 + 2 HNO3 -> 2 NaNO3 + H2O + CO2 (g)
Step 2: Split the soluble compounds into their respective ions.
Na2CO3 dissociates into 2 Na+ ions and 1 CO3^2- ion.
HNO3 dissociates into 1 H+ ion and 1 NO3^- ion.
NaNO3 remains as Na+ and NO3^- ions.
So the ionic equation becomes:
2 Na+ + CO3^2- + 2 H+ + 2 NO3^- -> 2 Na+ + 2 NO3^- + H2O + CO2 (g)
Step 3: Remove the spectator ions. Spectator ions are those that do not participate in the reaction and appear on both sides of the equation unchanged.
In this case, the Na+ and NO3^- ions appear on both sides unchanged, so they are spectator ions and can be removed.
The net ionic equation, with spectator ions removed, is:
CO3^2- + 2 H+ -> H2O + CO2 (g)
So, the net ionic equation for the given reaction is:
CO3^2- + 2 H+ -> H2O + CO2 (g)