Complete the following acid-base reaction with balanced molecular, total ionic and net ionic equations:

calcium hydroxide (aq) + acetic acid (aq) ----> ?

I know that calcium hydroxide is ca(OH)2 and that acetic acid is CH3COOH. I also know that one of the products in an acid-base rxn must be H2O. Need help with the rest!

The formula equation is:

Ca(OH)2 + 2HC2H3O2 --> Ca(HC2H3O2)2 + 2H2O

HC2H3O2 and H2O are molecular substances and you do not break them up into ions.

The ionic reaction is:
Ca^+2(aq) + 2OH^-(aq) + 2HC2H3O2 --> Ca^+2(aq) + 2C2H3O2^-(aq) + 2 H2O

Cancelling out the "spectator" (unchanged) ions, we get:

2OH^-(aq) + 2HC2H3O2 --> 2C2H3O2^-(aq) + 2 H2O

Dividing all coefficients by 2, we get:

OH^-(aq) + HC2H3O2 --> C2H3O2^-(aq) + H2O
We now have the net ionic equation.

I am happy. Good job.

Sure thing! Let's balance the equation and write the molecular equation, total ionic equation, and net ionic equation for the reaction.

First, let's write the balanced molecular equation:

Ca(OH)2 (aq) + 2CH3COOH (aq) → Ca(CH3COO)2 (aq) + 2H2O (l)

Now, let's write the balanced total ionic equation by breaking down the soluble compounds into their respective ions:

Ca2+ (aq) + 2OH- (aq) + 2CH3COOH (aq) → Ca2+ (aq) + 2CH3COO- (aq) + 2H2O (l)

Finally, let's write the balanced net ionic equation by removing the spectator ions (ions that are present on both sides of the equation and do not participate in the reaction):

2OH- (aq) + 2CH3COOH (aq) → 2CH3COO- (aq) + 2H2O (l)

So, the balanced molecular equation is Ca(OH)2 (aq) + 2CH3COOH (aq) → Ca(CH3COO)2 (aq) + 2H2O (l), the balanced total ionic equation is Ca2+ (aq) + 2OH- (aq) + 2CH3COOH (aq) → Ca2+ (aq) + 2CH3COO- (aq) + 2H2O (l), and the balanced net ionic equation is 2OH- (aq) + 2CH3COOH (aq) → 2CH3COO- (aq) + 2H2O (l).

Hope this helps, and remember, if all else fails, just break out your clown nose and chase away those chemistry blues! 🤡

To complete the acid-base reaction between calcium hydroxide (Ca(OH)2) and acetic acid (CH3COOH), you need to identify the products of the reaction and balance the chemical equation.

The reaction between calcium hydroxide and acetic acid can be represented as follows:

Ca(OH)2(aq) + 2CH3COOH(aq) ----> ? + ?

First, let's identify the products of the reaction. Calcium hydroxide consists of a calcium ion (Ca2+) and two hydroxide ions (OH-), while acetic acid contains an acetate ion (CH3COO-) and a hydronium ion (H3O+).

The reaction between these two compounds will result in the formation of water (H2O) and a calcium acetate compound. The balanced equation can be written as follows:

Ca(OH)2(aq) + 2CH3COOH(aq) ----> 2H2O(l) + Ca(CH3COO)2(aq)

Now, let's write the balanced equations in molecular, total ionic, and net ionic forms:

1. Molecular Equation:
Ca(OH)2(aq) + 2CH3COOH(aq) ----> 2H2O(l) + Ca(CH3COO)2(aq)

2. Total Ionic Equation:
Ca^2+(aq) + 2OH^-(aq) + 2CH3COOH(aq) ----> 2H2O(l) + Ca^2+(aq) + 2CH3COO^-(aq)

3. Net Ionic Equation:
2OH^-(aq) + 2CH3COOH(aq) ----> 2H2O(l) + 2CH3COO^-(aq)

In the net ionic equation, we have eliminated the spectator ions (Ca^2+), which are present on both sides of the equation.

So, the complete acid-base reaction, with balanced molecular, total ionic, and net ionic equations, is:
Molecular Equation:
Ca(OH)2(aq) + 2CH3COOH(aq) ----> 2H2O(l) + Ca(CH3COO)2(aq)

Total Ionic Equation:
Ca^2+(aq) + 2OH^-(aq) + 2CH3COOH(aq) ----> 2H2O(l) + Ca^2+(aq) + 2CH3COO^-(aq)

Net Ionic Equation:
2OH^-(aq) + 2CH3COOH(aq) ----> 2H2O(l) + 2CH3COO^-(aq)