New York citys 7.9 million people have a daily per capita consumption of 173 gallons of water. how many tons of sodium flouride would be requred per year to give this watr 1 part flourine per million parts water?
173 x 7.9 million x 365 = x
x/1 million = gallons of flourine
To calculate the amount of sodium fluoride required per year to achieve a concentration of 1 part fluoride per million parts of water, we need to follow these steps:
Step 1: Convert the daily per capita water consumption from gallons to liters.
1 gallon is approximately equal to 3.78541 liters. Therefore, the daily per capita consumption of water in liters would be:
173 gallons/day * 3.78541 liters/gallon = 653.43693 liters/day
Step 2: Calculate the total annual water consumption for New York City.
To find the total water consumption per year, we multiply the daily per capita consumption by the total population:
Total annual water consumption = 653.43693 liters/day * 7.9 million people * 365 days/year
Step 3: Convert the total annual water consumption from liters to cubic meters.
1 cubic meter is equal to 1000 liters. So, we divide the total annual water consumption by 1000 to convert liters to cubic meters:
Total annual water consumption in cubic meters = Total annual water consumption in liters / 1000
Step 4: Calculate the amount of sodium fluoride required.
Since we want 1 part fluoride per million parts of water, we can state that the concentration of fluoride is 1 ppm (parts per million). Therefore, the amount of sodium fluoride required can be calculated using the formula:
Amount of sodium fluoride required = Total annual water consumption in cubic meters * 1 ppm
Now, let's plug in the numbers to find the answer.
Amount of sodium fluoride required = (Total annual water consumption in liters / 1000) * 1 ppm
Please note that this calculation will provide an estimate, as it assumes uniform consumption throughout the year. Additionally, it's important to consult with water treatment professionals for accurate and specific requirements regarding sodium fluoride dosing.
Close but not quite there.
I assume 1 part flourine per million parts really means 1 part flouride ION per million parts.
First, convert 1 part flouride ion to sodium flouride since the problem specifies using NaF.
1 part F x (molar mass NaF/molar mass F) = 1 x 41/19 = = ??. I have something like 2.2 or so and that will be tons if we keep all the other units in tons.
Next, convert 7.9 million people using 173 gallons water/day to gallons of water used per day.
173 gal/person x 7.3*10^106 people = gallons used per day.
Convert gallons of water used per day to cubic feet of water used per day using the density of water which is 62.4 lbs/cubic foot.
Convert lbs water used per day to tons per day using 2000 lbs = 1 ton
Now you have tons of water used per day and you want 2.2 tons sodium flouride in each 1,000,000 tons of water to make the 1 ppm F.
Multiply that answer by 365 to obtain tons NaF (sodium flouride) used in a year.
Check my thinking. Check my work.