A basketball player with a free throw shooting percentage of 60% gets fouled and goes to the line
to shoot two free throws. What are the odds in favor of her making her first shot?
3/5
Idk that's y im asking
To calculate the odds in favor of the basketball player making her first shot, we need to first determine her free throw shooting percentage for a single free throw attempt.
Since her overall free throw shooting percentage is 60%, we can calculate the percentage for a single free throw by taking the square root of her overall percentage. In this case, the square root of 60% is approximately 77.46%. This represents the probability of her making a single free throw.
To calculate the odds in favor of making the first shot, we divide the probability of making the first shot by the probability of missing the first shot.
The probability of making the first shot is 77.46%.
To calculate the probability of missing the first shot, we need to subtract the probability of making the free throw from 100%. In this case, it would be 100% - 77.46% = 22.54%.
The odds in favor of making the first shot can be expressed as a ratio of the probability of making the first shot to the probability of missing the first shot.
Therefore, the odds in favor of her making her first shot are 77.46% / 22.54%.
prob of making first shot = 6/10 = 3/5
prob of NOT making it = 2/5
so the odds in favour of making it = 3:2