A car with good tires on a dry road can decelerate at about 5.0m/s/s when braking. If the car is traveling at 55miles/hour, how much time does it take the car to stop?

55 mph = 80.7 ft/s = 24.6 m/s
Divide the initial speed by the deceleration rate to get the time required.
(24.6 m/s)/(5.0 m/s^2) = ? seconds

4.92

(24.6 m/s)/(5.0 m/s^2) = 4.92 seconds

Therefore, it takes the car approximately 4.92 seconds to stop.

To calculate the time it takes for the car to stop, you need to divide the initial velocity by the deceleration rate.

First, convert the speed from miles per hour to meters per second.

55 mph is equal to 80.7 ft/s. To convert feet per second to meters per second, multiply by 0.3048 (since 1 meter is equal to 3.281 feet).

So, 80.7 ft/s = 80.7 ft/s × 0.3048 m/ft = 24.6 m/s.

Now, divide the initial speed (24.6 m/s) by the deceleration rate (5.0 m/s^2) to get the time required:

Time = 24.6 m/s ÷ 5.0 m/s^2 = 4.92 seconds.

Therefore, the car will take approximately 4.92 seconds to stop.

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