If 50.0 mL of a 0.10M solution of sodium chloride is mixed with 50.0 mL of 0.10 M magnesium chloride, what is the molar concentration of chloride in the resulting solution?
There will be 0.1 x 0.05 = 0.005 moles of Cl- from NaCl and 0.1x0.05x2 = 0.010 moles of Cl- from MgCl2 in the resulting 0.10 L of mixture. That is 0.015/0.1 = 0.15 moles per liter. Looks like 0.15 M is the answer.
Well, it seems like we have mixed some salty solutions here! Let's calculate the molar concentration of chloride in the resulting solution.
To do that, we can use the equation:
Molarity = moles of solute / volume of solution
First, let's find the moles of chloride in each solution. Since we have the molar concentration and volume, we can use the equation:
moles = Molarity x volume
For the sodium chloride solution, the moles of chloride are:
moles of chloride in NaCl = 0.10 M x 0.050 L = 0.005 mol
And for the magnesium chloride solution:
moles of chloride in MgCl2 = 0.10 M x 0.050 L = 0.005 mol
Now, let's add the moles of chloride from both solutions:
total moles of chloride = 0.005 mol + 0.005 mol = 0.010 mol
Finally, we need to calculate the molar concentration of chloride in the resulting solution. To do that, we divide the moles of chloride by the total volume of the resulting solution, which is 100 mL or 0.100 L:
Molarity of chloride in resulting solution = 0.010 mol / 0.100 L = 0.100 M
So, the molar concentration of chloride in the resulting solution is 0.100 M. It's chloride party time!
To find the molar concentration of chloride in the resulting solution, we need to determine the moles of chloride ions from each salt and add them together.
1. Determine the moles of chloride ions from sodium chloride:
- Moles of chloride = Molarity x Volume
- Moles of chloride from sodium chloride = 0.10 M x 50.0 mL = 0.010 moles
2. Determine the moles of chloride ions from magnesium chloride:
- Moles of chloride from magnesium chloride = 0.10 M x 50.0 mL = 0.010 moles
3. Add the moles of chloride ions from both salts:
- Total moles of chloride = Moles of chloride from sodium chloride + Moles of chloride from magnesium chloride
- Total moles of chloride = 0.010 moles + 0.010 moles = 0.020 moles
4. Calculate the resulting molar concentration of chloride in the solution:
- Molar concentration of chloride = Total moles of chloride / Total volume of solution
- Total volume of solution = 50.0 mL + 50.0 mL = 100.0 mL = 0.100 L
- Molar concentration of chloride = 0.020 moles / 0.100 L = 0.20 M
Therefore, the molar concentration of chloride in the resulting solution is 0.20 M.
To find the molar concentration of chloride in the resulting solution, we need to first calculate the moles of chloride ions in each solution and then combine them.
Let's start by calculating the moles of chloride ions in the sodium chloride solution.
Moles = Molar concentration × Volume (in liters)
= 0.10 M × 0.050 L
= 0.005 moles
Next, let's calculate the moles of chloride ions in the magnesium chloride solution.
Moles = Molar concentration × Volume (in liters)
= 0.10 M × 0.050 L
= 0.005 moles
Since both solutions have the same volume and molar concentration of chloride ions, the total moles of chloride ions in the resulting solution will be the sum of the moles from each solution.
Total moles of chloride ions = 0.005 moles + 0.005 moles
= 0.010 moles
Finally, we can calculate the molar concentration of chloride in the resulting solution.
Molar concentration = Total moles of chloride ions ÷ Total volume of solution (in liters)
= 0.010 moles ÷ 0.100 L
= 0.10 M
Therefore, the molar concentration of chloride in the resulting solution is 0.10 M.