Hydrogen gas, , reacts with nitrogen gas, , to form ammonia gas, , according to the equation
3H2+N2-2NH3
How many grams of can be produced from 2.90 of ?
You didn't complete the question. How many grams of ????? can be produced from 2.90 WHAT of what?
need help
To find the number of grams of NH3 that can be produced from 2.90 moles of H2, we need to use the stoichiometry of the balanced chemical equation.
According to the balanced equation:
3 H2 + N2 -> 2 NH3
We can see that 3 moles of H2 are required to produce 2 moles of NH3.
First, we need to calculate the number of moles of NH3 that can be produced from 2.90 moles of H2:
Moles of NH3 = (2.90 moles of H2) x (2 moles of NH3 / 3 moles of H2)
Moles of NH3 = 1.93 moles of NH3
Next, we can calculate the mass of NH3 produced using the molar mass of NH3:
Molar mass of NH3 = 14.01 g/mol + 3(1.01 g/mol) = 17.03 g/mol
Mass of NH3 = (1.93 moles of NH3) x (17.03 g/mol)
Mass of NH3 = 32.85 g
Therefore, 32.85 grams of NH3 can be produced from 2.90 moles of H2.
To determine the number of grams of ammonia gas that can be produced from a given amount of hydrogen gas, you need to use stoichiometry. In this case, we can use the balanced chemical equation to convert the given mass of hydrogen gas to the mass of ammonia gas.
First, we need to find the molar mass of hydrogen gas (H2) and ammonia gas (NH3).
Molar mass of H2:
H2 = 2(1.008 g/mol)
H2 = 2.016 g/mol
Molar mass of NH3:
NH3 = 1(14.01 g/mol) + 3(1.008 g/mol)
NH3 = 17.031 g/mol
Next, we need to convert the given mass of hydrogen gas to moles using the molar mass of H2:
Moles of H2 = Given mass of H2 / Molar mass of H2
Moles of H2 = 2.90 g / 2.016 g/mol
Moles of H2 ≈ 1.439 mol
According to the balanced chemical equation, the stoichiometric ratio between H2 and NH3 is 3:2. This means that for every 3 moles of H2, 2 moles of NH3 are produced.
Using this ratio, we can calculate the moles of NH3 that can be produced:
Moles of NH3 = (Moles of H2 / 3) * 2
Moles of NH3 = (1.439 mol / 3) * 2
Moles of NH3 ≈ 0.959 mol
Finally, we can convert the moles of NH3 to grams using the molar mass of NH3:
Mass of NH3 = Moles of NH3 * Molar mass of NH3
Mass of NH3 = 0.959 mol * 17.031 g/mol
Mass of NH3 ≈ 16.350 g
Therefore, approximately 16.350 grams of NH3 can be produced from 2.90 grams of H2.