Determine the molar concentration of ethanol (C2H6O) in a wine that is 14% ethanol by mass. The density of this wine is 0.93 g/cm^3.
Well, let's start by converting the mass percentage of ethanol to grams. If you have 100g of wine, 14% of that would be 14 grams of ethanol.
Now, we can determine the volume of the wine in liters using its density. Since the density is 0.93 g/cm^3 and we have 14 grams of ethanol, we can divide the mass (14g) by the density (0.93 g/cm^3) to find the volume in cm^3.
14g / 0.93 g/cm^3 ≈ 15.05 cm^3
Since 1 cm^3 is equal to 1 mL, we can say that the volume of the wine is approximately 15.05 mL.
Finally, to determine the molar concentration, we need to convert mL to L and calculate the number of moles of ethanol.
The molar mass of ethanol (C2H6O) is approximately 46.07 g/mol.
Volume (in L) = 15.05 mL / 1000 ≈ 0.01505 L
Moles of ethanol = mass of ethanol (in grams) / molar mass of ethanol
Moles of ethanol = 14g / 46.07 g/mol ≈ 0.304 mol
Molar concentration (in mol/L) = moles of ethanol / volume (in L)
Molar concentration = 0.304 mol / 0.01505 L ≈ 20.2 mol/L
So, the molar concentration of ethanol in the wine is approximately 20.2 mol/L.
Cheers! Just remember, alcohol gets better with some chemistry humor. So, always keep a balanced solution handy!
To determine the molar concentration of ethanol in the wine, we need to convert the mass percentage of ethanol to molar concentration.
Step 1: Calculate the moles of ethanol:
First, we need to calculate the mass of ethanol in the wine.
Given:
- Mass percent of ethanol = 14%
- Density of wine = 0.93 g/cm^3
Let's assume we have 100 g of wine, so the mass of ethanol in 100 g of wine can be calculated as:
Mass of ethanol = 14% of 100 g = 0.14 * 100 g = 14 g
Step 2: Convert the mass of ethanol to moles:
To convert the mass of ethanol to moles, we need to know the molar mass of ethanol (C2H6O).
The molar mass can be calculated as:
Molar mass of ethanol = (2 * Atomic mass of C) + (6 * Atomic mass of H) + Atomic mass of O
Using the atomic masses from the periodic table:
Molar mass of ethanol = (2 * 12.01 g/mol) + (6 * 1.01 g/mol) + 16.00 g/mol
Molar mass of ethanol = 24.02 g/mol + 6.06 g/mol + 16.00 g/mol
Molar mass of ethanol = 46.08 g/mol
Using the molar mass, we can calculate the number of moles of ethanol:
Number of moles of ethanol = Mass of ethanol / Molar mass of ethanol
Number of moles of ethanol = 14 g / 46.08 g/mol
Step 3: Calculate the volume of wine:
We are given the density of the wine as 0.93 g/cm^3, and we know the mass of the wine is 100 g. Thus, we can calculate the volume of the wine:
Volume of wine = Mass of wine / Density of wine
Volume of wine = 100 g / 0.93 g/cm^3
Step 4: Calculate the molar concentration:
Finally, we can calculate the molar concentration of ethanol in the wine:
Molar concentration of ethanol = Number of moles of ethanol / Volume of wine
Now you can substitute the values you have calculated into the equation to find the molar concentration of ethanol in the wine.
To determine the molar concentration of ethanol in the wine, we need to convert the mass percentage of ethanol to molarity. The molar concentration, also known as the molarity (M), is defined as the number of moles of solute (ethanol) per liter of solution (wine).
To get started, let's assume we have 100 g of the wine. This makes calculations easier while maintaining the relative proportions. We can also convert the density of the wine to find the volume of the solution using the formula:
Density = mass / volume
Given that the density of the wine is 0.93 g/cm^3, we can rearrange the formula to solve for volume:
Volume = mass / density
Volume = 100 g / 0.93 g/cm^3
Volume = 107.53 cm^3
Now, let's determine the mass of the ethanol in the 100 g of wine. Since the wine is 14% ethanol by mass, we can calculate the mass of ethanol as follows:
Mass of ethanol = 14% of 100 g
Mass of ethanol = 0.14 * 100 g
Mass of ethanol = 14 g
Next, we need to convert the mass of ethanol to moles. To do this, we divide the mass of ethanol by its molar mass. The molar mass of ethanol (C2H6O) can be calculated by summing the atomic masses of its constituent elements:
Molar mass of ethanol (C2H6O) = (2 * Atomic mass of carbon) + (6 * Atomic mass of hydrogen) + (1 * Atomic mass of oxygen)
Looking up the atomic masses, we find:
Atomic mass of carbon (C) = 12.01 g/mol
Atomic mass of hydrogen (H) = 1.008 g/mol
Atomic mass of oxygen (O) = 16.00 g/mol
Plugging in the values:
Molar mass of ethanol (C2H6O) = (2 * 12.01 g/mol) + (6 * 1.008 g/mol) + (1 * 16.00 g/mol)
Molar mass of ethanol (C2H6O) ≈ 46.07 g/mol
Now, we can calculate the moles of ethanol:
Moles of ethanol = Mass of ethanol / Molar mass of ethanol
Moles of ethanol = 14 g / 46.07 g/mol
Moles of ethanol ≈ 0.303 mol
Finally, we can calculate the molar concentration (molarity) using the volume of the solution:
Molar concentration of ethanol = Moles of ethanol / Volume of solution
Since we assumed 100 g of wine, which is equivalent to 107.53 cm^3 (as calculated earlier), we have:
Molar concentration of ethanol = 0.303 mol / 107.53 cm^3
Molar concentration of ethanol ≈ 0.00282 M
Therefore, the molar concentration of ethanol in the wine is approximately 0.00282 M.
14% by mass means 14 g ethanol per 100 g solution. So the 100 g consists of 14 g ethanol + 86 g water. How many moles are in 14 g? 14/molar mass ethanol.
How many cc are in 100 g soln with a density of 0.93 g/cc?
Then molarity = moles/L solution.