Eugenol, the active ingredient in cloves, has a formula of C10H12O2. What is the boiling point of a solution containing 1.14g of eugenol dissolved in 10.0g of benzene? The boiling point of benzene is 80.1C and the boiling point elevation constant for benzene is 2.53C/m.

I got 180C, but it was wrong also.

delta T = Kb*molality.

You have Kb. molality = moles/kg solvent. You have kg solvent. Moles can be determined by grams eugenol/molar mass eugenol. Then add delta T to 80.1 degrees to obtain the boiling point of the solution.

To find the boiling point of the solution, you need to consider the boiling point elevation caused by the presence of the dissolved eugenol in the benzene solvent. The boiling point elevation is calculated using the following formula:

ΔTb = Kb * m

Where:
ΔTb is the boiling point elevation,
Kb is the boiling point elevation constant for the solvent (benzene in this case), and
m is the molality of the solution (moles of solute per kilogram of solvent).

First, let's calculate the molality (m) of the eugenol solution:

Step 1: Calculate the moles of eugenol:
Moles = mass / molar mass
Moles = 1.14g / 164.20 g/mol (molar mass of eugenol)
Moles = 0.00694 mol

Step 2: Calculate the molality:
molality (m) = moles of solute / (mass of solvent in kg)
mass of solvent = 10.0g = 0.01kg
molality (m) = 0.00694 mol / 0.01 kg
molality (m) = 0.694 mol/kg

Now that we have the molality (m) of the solution, we can calculate the boiling point elevation (ΔTb):

ΔTb = Kb * m
ΔTb = 2.53C/m * 0.694 mol/kg
ΔTb = 1.75522 C

Finally, to find the boiling point of the solution, we add the boiling point elevation to the boiling point of the pure solvent:

Boiling point of solution = boiling point of solvent + boiling point elevation
Boiling point of solution = 80.1 C + 1.75522 C
Boiling point of solution ≈ 81.86 C

Therefore, the boiling point of the solution containing 1.14g of eugenol dissolved in 10.0g of benzene is approximately 81.86°C.