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A turntable reaches an angular speed of 33.3 rpm, in 2.0 s, starting from rest.

(a) Assuming the angular acceleration is constant, what is its magnitude?

(b) How many revolutions does the turntable make during this time interval?

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Megan
1 answer

  1. a.
    Angular acceleration
    =(ωfinal-ωinitial)/time
    =(33.3*2π radians/60 sec. - 0)/2 sec.
    = 1.74 rad/s/s
    b.
    Number of turns
    = (ωfinal+ωinitial)/2 * time radians
    note: ω is in rad/s

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