How many molecules of glycerol(C6H8O3) would be present in 1L of a 1M glycerol solution? a. 1 b. 14 c. 92 d. 1*10^7 6.02*10^23
moles = M x L.
After you know moles, then there are 6.02 x 10^23 molecules in 1 mole of anything.
6.02 x 10^23 is the basic molecules in one mole of anything
To calculate the number of molecules of glycerol present in a 1M solution, we need to use Avogadro's number (6.02x10^23), which represents the number of molecules in one mole of a substance.
First, we need to convert the given concentration (1M) into moles of glycerol:
1M glycerol solution means there is 1 mole of glycerol dissolved in 1 liter of solution.
Therefore, we have 1 mole of glycerol in 1 liter.
Next, we convert from moles to molecules using Avogadro's number:
1 mole of glycerol = 6.02x10^23 molecules of glycerol
Since we have 1 mole of glycerol, the number of molecules is:
1 mole x 6.02x10^23 molecules/mole = 6.02x10^23 molecules
Therefore, there would be 6.02x10^23 molecules of glycerol in 1 liter of a 1M glycerol solution.
So, the correct answer is d. 6.02x10^23.
To determine the number of molecules of glycerol in a given solution, we need to understand the relationship between molarity, volume, and Avogadro's number.
Molarity (M) is a measure of the concentration of a solution and is defined as the number of moles of solute divided by the volume of the solution in liters. In this case, the molarity of the glycerol solution is given as 1M.
Avogadro's number (6.02 x 10^23) is the number of particles (atoms, molecules, ions, or formula units) in one mole of a substance.
To calculate the number of molecules, you would need to use the following formula:
Number of molecules = (Molarity) x (Avogadro's number) x (Volume in liters)
Given:
Molarity of the glycerol solution = 1M
Volume of the solution = 1L
Now, substitute the given values into the formula to find the number of molecules:
Number of molecules = (1M) x (6.02 x 10^23) x (1L)
Number of molecules = 6.02 x 10^23 molecules
Therefore, the correct answer is d. 1*10^7 (6.02 x 10^23).