Most hummingbirds can fly with speeds of nearly 50.0 km/h. Suppose a hummingbird flying with a velocity of 50.0 km/h in the forward direction accelerates uniformly at 9.20 m/s^2 in the backward direction until it comes to a hovering stop. What is the hummingbird's displacement?
4 answers

Initial velocity, u = 50 km/h = 13.89 m/s
Final velocity, v = 0 km/h = 0 m/s
Acceleration, a = 9.2 m/s
Displacement, S
2aS = v²u²
S=(v²u²)/(2a)
Can you do the rest?

10.48m

we use the 4th kinematic equation :vf'2
=vi'2=2ax... but first we have to rearrange it :x+vf'2vi /2a
+50'2 0 /2(9.20)
+2500/18.4
+136km
hop this is right :)


vi = 50 km/h = 13.9 m/s
vf = 0
a = 9.20 m/s^2
d = ?
vf^2 = vi^2 + 2ax
0=13.9^2 + 2(9.20)x
0 =193  18.4x
18.4x = 193
divide both sides by 18.4
x = 10.5
displacement = 10.5 m
notice: (all measurements are rounded to the smallest number of significant figures)