A startled armadillo leaps upward, rising .544 m in eh first .200s
a) What is its initial speed as it leaves the ground?
b)What is its speed at the height of .544m?
c) How much higher does it go?
Solve the first part
d= vo*t  1/2 9.8 t^2
you know d, and t.
solve for vo.
For the second part, vf=vo 9.8 t
For the final height, the vf is zero, so
Vf=vot 9.8 t solve for t then put it in the displacement equation to get max height.
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2 answers

1.74
3.7
0.698 👍
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wow, anonymous you're so helpful. not. work and stepbystep would help.
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