an open box contains 80cm^3 and is made from a square piece of tinplate with 3cm squares cut from each of its 4 corners. Find the dimensions of the original piece of tinplate.
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2 answers

I see the equation
3(x6)(x6) = 80
3(x^2  12x + 36) = 80
3x^2  36x + 108  80 = 0
3x^2  36x + 28 = 0
Use the quadratice formula to find x
I got x=11.164
check 11.1646 = 5.164
so the box is 5.164x5.164x3
which gives 80 👍
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answered by Reiny 
Let the side of the square plate be x cm.
The height of the box is 3 cm.
The length & width are both (x6) cm.
volume = length*width*height
=3*(x6)*(x6)
=80
x can then be obtained by solving
3(x6)(x6)=80 👍
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answered by MathMate
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