Graph the line containing the given pair of points and find the slope

(1,0) , (-5, -3)

-3-0/-5-1 + -3/4 so the slope would be M=-3/4 but how do you graph -3/4? Am I looking at this correctly.

I disagree with your math. Isn't -5-1=-6? m=-3/-6= 1/2

Now, graphing the line. mark this point on a graph paper (1,0). Now mark this point (-5,-3). Put ruler on the graph paper such that the edge touches each point. Draw the connecting line.

To graph the line containing the pair of points (1,0) and (-5,-3), we can follow these steps:

Step 1: Plot the points on a coordinate plane. The first point, (1,0), has an x-coordinate of 1 and a y-coordinate of 0. The second point, (-5,-3), has an x-coordinate of -5 and a y-coordinate of -3.

Step 2: Use a ruler to draw a straight line through the two points. This line represents the graph of the equation.

Now, to find the slope of this line, you correctly calculated the change in y divided by the change in x as follows:

(-3 - 0) / (-5 - 1) = -3 / -6 = 1/2

So, the slope of the line is 1/2. The value you mentioned, -3/4, is incorrect.

To graph a slope of 1/2, you can start at any point on the line and use the slope to find other points. For example:

- Starting at (1,0), you can move one unit to the right (because the denominator of the slope is 2) and then move up half a unit (because the numerator of the slope is 1). This will give you the point (2, 1/2).
- Starting at (-5,-3), you can move one unit to the right and then move up half a unit. This will give you the point (-4, -2.5).

By connecting these points with a straight line, you will have graphed the line with a slope of 1/2 passing through the given points (1,0) and (-5,-3).