If you were to expend 10 Joules of work to push a 1-coulomb charge against an electric field, what would be its voltage with respect to its voltage in its starting position? When released, what will be its kinetic energy if it flies past its starting position?
A one volt change in potential means that the potential electrostatic energy changes by one Joule per Coulomb.
Since you would be pushing the charge against the field, and expend 10 J, the voltage would be 10 Volts higher.
That 10 J will be converted to kinetic energy if the charge flies back to the starting position without friction.
i need help 4 physical science
When released, what will be its kinetic energy if it flies past its starting position?
To determine the voltage of the charge with respect to its starting position, we can use the formula for electric potential energy:
Electric potential energy (PE) = q * V
where q is the charge and V is the voltage. We can rearrange the formula to solve for V:
V = PE / q
Given that 10 Joules of work is done to push a 1-coulomb charge against the electric field, the electric potential energy change (ΔPE) is equal to 10 Joules.
Substituting these values into the formula:
V = ΔPE / q
V = 10 Joules / 1 Coulomb
V = 10 Volts
So, the voltage of the charge with respect to its starting position is 10 Volts.
When the charge is released and flies past its starting position, its potential energy is converted into kinetic energy. The kinetic energy (KE) of an object can be calculated using the formula:
KE = 0.5 * m * v^2
where m is the mass of the object and v is its velocity. Since the problem does not provide the mass of the charge, we'll assume it to be negligible. Therefore, the kinetic energy depends only on the velocity.
In this case, if the charge is released, it will accelerate due to the electric field. The kinetic energy it possesses when it flies past its starting position can be calculated using the work-energy theorem:
Work done on the charge (W) = ΔKE
Given that 10 Joules of work is done on the charge, the change in kinetic energy (ΔKE) is equal to 10 Joules.
Therefore, the kinetic energy of the charge when it flies past its starting position will also be 10 Joules.