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1. Use kinematics to calculate the height for the firstball,
   
   which is Vf=0
   
   a=9.8
   
   t=1.5
   because you take the total time it take to go up and come back down and divide it by 2. 3/2 = 1.5
   
   
   
   getting an initial velocity of
   Voy= 14.7m/s
   V = t(9.8)
   = 1.5(9.8)
   = 14.7
   
   
   This must have the same velocity in the y to get that height of 11.025m calculated in part 1, so just use trig to get the answer.
   
   
   14.7/sin30
   =29.4 m/s

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   answered by j

   Sep 25, 2012

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