it says write the equation of the vertical line that passes through the point (7,-3). what do i need to start it off?

find the equation for the line with undefined slope and passing through the point (-1,-2). what do i need to start that off?

what equation do i use to find the slope-intercept?

whats the point-slope form?

joj

To start off writing the equation of a vertical line passing through a point:

1. Recall that a vertical line has an undefined slope.
2. Identify the x-coordinate of the given point, which represents the x-coordinate of the vertical line. In this case, the x-coordinate is 7.
3. The equation of a vertical line passing through a specific x-coordinate is simply x = c, where c represents the x-coordinate. So, the equation for the vertical line passing through (7,-3) would be x = 7.

To start off finding the equation for a line with an undefined slope passing through a given point:

1. Recall that a line with an undefined slope is a vertical line.
2. Identify the x-coordinate of the given point, which represents the x-coordinate of the vertical line. In this case, the x-coordinate is -1.
3. The equation for a vertical line passing through a specific x-coordinate is x = c, where c represents the x-coordinate. So, the equation for the line passing through (-1,-2) would be x = -1.

To find the equation in slope-intercept form (y = mx + b) for a line, you need the following information:

1. The slope (m) of the line.
2. The y-coordinate (y) and x-coordinate (x) of a point on the line.
3. Once you have the slope and a point, you can substitute the values into the equation y = mx + b and solve for the y-intercept (b).

The point-slope form of an equation of a line is:

y - y₁ = m(x - x₁)

In this form, the equation represents a line with:
- m as the slope of the line,
- (x₁, y₁) as a point on the line.

You can use this form to find the equation of a line given a known point and the slope. Remember to substitute the values of the slope and point into the equation.

my last line should have been

3y + 9 = 2x - 10

any vertical line has an undefined slope and always has the form x = c, where c is a constant.

All you need is a point, then simply state it as x = 'the x of the given point'

so for your first one : x = 7
for the second x = -1

slope-intercept form looks like this
y = mx + b, where m is the slope and b is the y-intercept

e.g. y = 4x + 9
the slope is 4 and the y-intercept is 9

the point-slope form is one of the best ways to find the equation of a straight line, given the slope and a point

e.g. given the point (5,-3) and slope of 2/3, find the equation

y - (-3) = (2/3)(x - 5)
3(y+3) = 2(x-5)
3y + 3 = 2x - 10

you can now re-arrange it to end up with any version they ask for.