# distance = rate x time or

d = r*t

car traveling 40 mi/hr goes 40 mi/hr x 1.5 hrs head start or 60 miles head start.

Let t = time bus and car travel.

car travels distance of r*t = 40*t.

Car already had 60 mi head start.

Total distance car traveled is 60 + 40*t.

distance bus travels in t hours is 60*t.

distance for bus = distance for car so set them equal.

60 + 40*t = 60*t and solve for t.

Post your work if you get stuck.

I need help with the following question

How long will it take a bus traveling at 60 mph to overtake a car traveling at 40mph if the car had a 1.5 hour head start?

## traveling at 60 mph, how long will it take to travel 210 miles?

## 30

## To solve the question, we can set up an equation where the distance traveled by the bus is equal to the distance traveled by the car:

Distance for bus = Distance for car

Since we want to find the time it takes for the bus to overtake the car, let's use the variable "t" to represent the time traveled by both the bus and the car.

The distance traveled by the bus can be computed by multiplying its rate (60 mph) by the time it traveled (t).

Distance for bus = 60t

Similarly, the distance traveled by the car can be calculated by multiplying its rate (40 mph) by the time it traveled (t + 1.5).

Distance for car = 40(t + 1.5)

Since we know that the car had a 1.5-hour head start, we add that to the time traveled by the car.

Now, we can set up the equation:

60t = 40(t + 1.5)

We can solve this equation to find the value of "t" which represents the time it takes for the bus to overtake the car.