# I'm not sure if I have this correct I have to solve each literal equation for the indicated variable. A=1/2h(B+b)variable is (b). I have the answer as:

2A=h(B1+b2)
2A/h=B1+b2
(2A/h)-b2=B1
Is this correct?

weren't you supposed to solve for "b"?

that would be

b = (2A - Bh)/h or 2A/h - B

(looks similar in pattern to your last line)

## Yes, you are correct. The equation A = (1/2)h(B + b) can be solved for the variable b. Here's how you can solve it step by step:

1. Distribute the 1/2 to both terms inside the parentheses:
A = (1/2)hB + (1/2)hb

2. Move the (1/2)hB term to the other side of the equation by subtracting it from both sides:
A - (1/2)hB = (1/2)hb

3. Multiply both sides of the equation by 2 to eliminate the fraction:
2(A - (1/2)hB) = hb

4. Distribute the 2 on the left side:
2A - hB = hb

5. Now, isolate the variable b by subtracting hb from both sides:
2A - hB - hb = 0

6. Factor out b on the left side:
2A - (h + 1)b = 0

7. Divide both sides of the equation by (h + 1) to solve for b:
b = (2A - hB) / (h + 1)

So, the correct answer for solving the equation A = (1/2)h(B + b) for b is:
b = (2A - hB) / (h + 1)

Your answer of b = (2A/h) - b2 is incorrect. Make sure you carefully distribute and isolate the variables to get the desired solution.