Carbon-12 contains 6 protons and 6 neutrons. The radius of the nucleus is approximately 2.7 (femtometers) and the radius of the atom is approximately 70 (picometers).
The volume of the nucleus is 8.2×10^−8 pm^3
And the volume of the atom is 1.4×10^6 pm^3
I found the volumes but I also need to know what percent of the atom that the nucleus makes up.
Any help would be greatly appreciated!
The Percent is 5.9X10^-12
[V(nucleus)/V(atom)]x100% = answer
TO FIND THE % OF THE ATOM THAT THE NUCLEUS MAKES UP YOU NEED TO DIVIDE THE MASS OF THE PART YOU ARE TRYING TO FIGURE OUT BY THE WHOLE MASS OF THE NUCLEUS TIMES 100.
That's how I did it but the computer said it was wrong. I guess I'll have to ask the teacher about it. Thanks for your help!
To find the percentage of the atom that the nucleus makes up, we can use the formula:
Percentage = (Volume of Nucleus / Volume of Atom) x 100
Given that the volume of the nucleus is 8.2×10^−8 pm^3 and the volume of the atom is 1.4×10^6 pm^3, we can substitute these values into the formula:
Percentage = (8.2×10^−8 pm^3 / 1.4×10^6 pm^3) x 100
Now, let's solve this equation step by step:
First, convert the volume of the nucleus to picometers cubed:
8.2×10^−8 pm^3 = 8.2×10^−8 x 10^12 (convert femtometers to picometers)
= 8.2×10^4 pm^3
Now substitute the values into the equation:
Percentage = (8.2×10^4 pm^3 / 1.4×10^6 pm^3) x 100
Simplify:
Percentage = 0.0586 x 100
= 5.86%
So, the nucleus makes up approximately 5.86% of the total volume of the carbon-12 atom.