Net Ionic equations for..
1. Co(NO3)2 + NH3 --> ??
2. Cu(NO3)2 + NH3 --> ??
3. Ni(NO3)2 + NH3 --> ??
I can balance equations, I just don't know what goes on the products side.
cunhnhnhnooo
To determine the net ionic equations for the given reactions, we need to determine the products formed when the compounds react.
1. Co(NO3)2 + NH3:
Co(NO3)2 is a salt of cobalt and nitrate ions, and NH3 is ammonia. When they react, they form cobalt(II) hydroxide [Co(OH)2] and ammonium nitrate [NH4NO3]. The net ionic equation can be written as:
Co^2+ (aq) + 2OH^- (aq) → Co(OH)2 (s)
2. Cu(NO3)2 + NH3:
Cu(NO3)2 is a salt of copper and nitrate ions. When it reacts with ammonia (NH3), it forms a complex ion called tetraamminecopper(II) ion [Cu(NH3)4^2+]. The net ionic equation is:
Cu^2+ (aq) + 4NH3 (aq) → Cu(NH3)4^2+ (aq)
3. Ni(NO3)2 + NH3:
Ni(NO3)2 is a salt of nickel and nitrate ions. When it reacts with ammonia (NH3), it forms a complex ion called tetraamminenickel(II) ion [Ni(NH3)4^2+]. The net ionic equation can be written as:
Ni^2+ (aq) + 4NH3 (aq) → Ni(NH3)4^2+ (aq)
Note: The net ionic equations represent the overall reaction between the ions involved, omitting spectator ions like nitrate (NO3^-) and ammonium (NH4+).
To determine the net ionic equations for the given chemical reactions, we need to identify the spectator ions and the ions that actually participate in the reaction. The spectator ions are those that appear unchanged on both the reactant and product sides of the equation. The net ionic equation only includes the ions involved in the reaction and omits the spectator ions.
Let's break down each reaction and determine the net ionic equation:
1. Co(NO3)2 + NH3 → ??
First, let's write out the ionic compounds in the reaction and split them into their respective ions:
Co(NO3)2→ Co^2+ + 2NO3^-
NH3 → NH4+ + OH-
Now, let's find the common ions between the two compounds. In this case, there are no common ions. Therefore, we can directly write the net ionic equation:
Co^2+ + 2NH3 → Co(NH3)2^2+
The net ionic equation for this reaction is Co^2+ + 2NH3 → Co(NH3)2^2+.
2. Cu(NO3)2 + NH3 → ??
Following the same procedure, let's split the ionic compounds into their respective ions:
Cu(NO3)2 → Cu^2+ + 2NO3^-
NH3 → NH4+ + OH-
Now, let's identify the common ions between the two compounds. In this case, the sulfate ion (SO4^2-) is the common ion. Hence, it is the spectator ion that we can eliminate. Thus, the net ionic equation is:
Cu^2+ + 2NH3 → Cu(NH3)2^2+
The net ionic equation for this reaction is Cu^2+ + 2NH3 → Cu(NH3)2^2+.
3. Ni(NO3)2 + NH3 → ??
Similarly, let's split the ionic compounds into their ions:
Ni(NO3)2 → Ni^2+ + 2NO3^-
NH3 → NH4+ + OH-
Identify the common ions between the two compounds. In this case, the nitrate ion (NO3-) is the common ion. Thus, it is a spectator ion and can be removed. Therefore, the net ionic equation is:
Ni^2+ + 2NH3 → Ni(NH3)2^2+
The net ionic equation for this reaction is Ni^2+ + 2NH3 → Ni(NH3)2^2+.
Remember that these net ionic equations represent only the ions directly involved in the reaction and do not include the spectator ions.
Just products?
Are you studying complex formation? Co is known with both 6 and 4 NH3 complexed. Ni is the same. Cu is square planar (with NH3) and coordination number of 4.
1. Co(NH3)6+2 + NO3^-
2. Cu(NH3)4^+2 + NO3^-
3. Ni(NH3)6^+2 + NO3^-