A person hits a 45-g golf ball. The ball comes down on a tree root and bounces straight up with an initial speed of 14.0 m/s. Determine the height the ball will rise after the bounce
The equation is
height= 1/2 velocity^2 / g
where g is 9.8m/s^2
2021 people
To determine the height the golf ball will rise after the bounce, we can use the equation:
height = (1/2) * velocity^2 / g
Let's plug in the values we have:
velocity = 14.0 m/s
g = 9.8 m/s^2
Now, substitute these values into the equation and solve for the height:
height = (1/2) * (14.0 m/s)^2 / (9.8 m/s^2)
= (1/2) * 196 m^2/s^2 / 9.8 m/s^2
= 98 m^2/s^2 / 9.8 m/s^2
= 10 m
Therefore, the height the ball will rise after the bounce is 10.0 meters.
5677
mgh=1/2mv^2
gh = 1/2v^2
9.81 x h = (0.5)(15.0 m/s)^2
9.81/9.81 x h = 56.25/9.81
h = 5.7