# When 1180 J of heat are added to one mole of an ideal monatomic gas, its temperature increases from 272 to 292 K. Find the work done by the gas during this process.

I know the specific heat is Q/delta T, so C = (1180 J)/(20K) = 59. This seems like any easy problem, but now I'm stuck on what to do next.

Hmmm. It seems to me you are fishing for answers. Your bait of Q/deltaT is not good enough. Recheck your text.

For a given mass,

Heat in = Work out + delta U

delta U is the change in internal energy. You can calculate it as

Delta U = Cv delta T

where Cv is the specific heat at constant volume. This formula is valid even though your problem may involve a changing volume.

In your monatomic case, Cv = 3/2 R

R = 8.317 J/ mole K is the universal gas constant.

Solve for Work out